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A spaceship takes off vertically from rest with an acceleration of 30.0 m/s 2 . What magnitude of force F is exerted on a 53.0 kg astronaut during takeoff?

Answer :

asuwafoh

Answer:

1590 N.

Explanation:

Force: This can be defined as the product of mass and the acceleration of a body. The S.I unit of Force is Newton (N).

The formula of force is given as

F = ma ........................ Equation 1

Where F = Force, m = mass of the astronaut, a = takeoff acceleration if the astronaut.

Given: m = 53.0 kg, a = 30 m/s²

Substitute into equation 1

F = 53(30)

F = 1590 N.

Hence the force exerted on the astronaut = 1590 N.

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