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Find the real solutions of the equation. 8 x Superscript 2 divided by 3 Baseline minus 63 x Superscript 1 divided by 3 Baseline minus 8 equals 0 What is the solution​ set? Select the correct choice below and fill in any answer boxes within your choice.

Answer :

Answer:

-((sq.rt.4737)-63)/16 & ((sq.rt.4737)-63)/16

Step-by-step explanation:

8x^2/3 - 63x^1/3 - 8 = 0

Have to use the quadratic formula

(-b +- sq.rt.b^2-4ac)/2a

gives -((sq.rt.4737)-63)/16

and ((sq.rt.4737)-63)/16

where a = 8/3, b = -63/3, & c = -8

hope that's right.

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