Answer :
Answer:
0 N/C
Explanation:
Parameters given:
[tex]q_1 = -8.00 * 10^{-7} C[/tex]
[tex]x_1 = 6.00 cm[/tex]
[tex]q_2 = +8.00 * 10^{-7} C[/tex]
[tex]x_2 = 21 cm[/tex]
The distance between [tex]q_1[/tex] and [tex]q_2[/tex] is
[tex]21 - 6 = 15cm[/tex]
Electric field is given as
[tex]E = \frac{kq}{r^2}[/tex]
r = 15/2 = 7.5cm = 0.075m
The electric field at their midpoint due to [tex]q_1[/tex] is:
[tex]E = \frac{9 * 10^9 * -8.0 * 10^{-7}}{0.075^2}[/tex]
[tex]E_1[/tex] = [tex]-1.28 * 10^6 N/C[/tex]
The electric field at the midpoint due to [tex]q_2[/tex] is:
[tex]E = \frac{9 * 10^9 * 8.0 * 10^{-7}}{0.075^2}[/tex]
[tex]E_2[/tex] = [tex]1.28 * 10^6 N/C[/tex]
The net electric field will be:
E = [tex]E_1[/tex] + [tex]E_2[/tex]
E = [tex]-1.28 * 10^6[/tex] + [tex]1.28 * 10^6[/tex]
E = 0 N/C