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Two particles are fixed to an x axis: particle 1 of charge −8.00 ✕ 10⁻⁷ C at x = 6.00 cm, and particle 2 of charge +8.00 ✕ 10⁻⁷ C at x = 21.0 cm.
Midway between the particles, what is their net electric field?

Answer :

Answer:

0 N/C

Explanation:

Parameters given:

[tex]q_1 = -8.00 * 10^{-7} C[/tex]

[tex]x_1 = 6.00 cm[/tex]

[tex]q_2 = +8.00 * 10^{-7} C[/tex]

[tex]x_2 = 21 cm[/tex]

The distance between [tex]q_1[/tex] and [tex]q_2[/tex] is

[tex]21 - 6 = 15cm[/tex]

Electric field is given as

[tex]E = \frac{kq}{r^2}[/tex]

r = 15/2 = 7.5cm = 0.075m

The electric field at their midpoint due to [tex]q_1[/tex] is:

[tex]E = \frac{9 * 10^9 * -8.0 * 10^{-7}}{0.075^2}[/tex]

[tex]E_1[/tex] = [tex]-1.28 * 10^6 N/C[/tex]

The electric field at the midpoint due to [tex]q_2[/tex] is:

[tex]E = \frac{9 * 10^9 * 8.0 * 10^{-7}}{0.075^2}[/tex]

[tex]E_2[/tex] = [tex]1.28 * 10^6 N/C[/tex]

The net electric field will be:

E = [tex]E_1[/tex] + [tex]E_2[/tex]

E = [tex]-1.28 * 10^6[/tex] + [tex]1.28 * 10^6[/tex]

E = 0 N/C

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