Answer :
Explanation:
The given data is as follows.
Length of beam, (L) = 5.50 m
Weight of the beam, ([tex]W_{b}[/tex]) = 332 N
Weight of the Suki, ([tex]W_{s}[/tex]) = 505 N
After crossing the left support of the beam by the suki then at some overhang distance the beam starts o tip. And, this is the maximum distance we need to calculate. Therefore, at the left support we will set up the moment and equate it to zero.
[tex]\sum M_{o} = 0[/tex]
[tex]-W_{s} \times x + W_{b} \times 1.5[/tex] = 0
x = [tex]\frac{W_{b} \times 1.5}{W_{s}}[/tex]
= [tex]\frac{332 N \times 1.5}{505 N}[/tex]
= 0.986 m
Hence, the suki can come (2 - 0.986) m = 1.014 from the end before the beam begins to tip.
Thus, we can conclude that suki can come 1.014 m close to the end before the beam begins to tip.