Find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified line. y = x + 1, y = 0, x = 0, x = 8; about the x-axis V = Sketch the region. Sketch the solid, and a typical disk or washer.

Answer :

Answer:

Step-by-step explanation:

the region is bounded by

. y = x + 1, y = 0, x = 0, x = 8;

and rotated about x axis.

The limits for x are from 0 to 8

The region is between x+1 and 0

Hence using washer method volume

= [tex]V=\pi\int\limits^8_0 {(x+1)^2-0^2} \, dx \\=\pi*\frac{(x+1)^3}{3}[/tex]

substitute limits

V=[tex]\frac{\pi}{3}9^3\\= 243\pi[/tex]

cubic units.

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Answer:

The volume of the region is 763.02 cubic units.

Step-by-step explanation:

Given information:

Volume (V) of solid is obtained by the given curve about the line:

[tex]y=x+1[/tex]

At, [tex](y=0 ,x=0 , x=8)[/tex]

The region is between [tex]x+1[/tex] and [tex]0[/tex].

Hence, using Washer method ,

volume:

[tex]V=\pi \int\limits^0_8 {(x+1)^2}-0^2 \, dx[/tex]

[tex]V=\pi \times \frac{(x+1)^3}{3}[/tex]

On substituting limits , we get

[tex]V=243\pi[/tex] [tex]cubic[/tex] [tex]unit[/tex]

[tex]V=763.02[/tex] [tex]cubic[/tex] [tex]unit[/tex].

So, the volume of the region is 763.02 cubic units.

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