VB theory predicts sp3 hybridization in thionyl chloride (SOCl2) based on its trigonal pyramidal molecular geometry. However, there are 10 valence electrons around the Sulphur atom (hypervalent) and an S=O double bond is present. Explain in words how VB theory is able to account for these observations? Bonus: Which specific atomic orbitals of Sulphur and Oxygen participate in the S=O double bond? (Hint: there are 2 possible answers)

Answer :

Answer: d-orbitals account for the sulphur- oxygen double bond.

Explanation:

Looking at the nature of bonding in SOCl2, the sulphur is bonded to two chlorine atoms and one oxygen atom. The sulphur has a lone pair of electrons. There are four bonds and four electron pairs if we don't count the lone pair on sulphur. This leads to a tetrahedral shape. However, if we invoke a valence state in which d orbitals are involved and the thionyl chloride is still sp3 hybridized, then we will have one electron in the d-orbital which overlaps with a 2p electron from oxygen to form the double bond. The four sp3 orbitals accommodate eight electrons including the lone pair on sulphur while the d-orbital accommodates the remaining two electrons from the pi-bond thereby completing the ten electrons. The approach of canonical structures and charge separation shown in the image attached

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