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Some pipe organs create sounds lower than humans can hear. This ""infrasound"" can still create physical sensations. What is the fundamental frequency of the sound from an open-open pipe that is 32 feet long (a common size for large organs)? What length open-closed tube is necessary to produce this note? Assume a sound speed of 343 m/s.

Answer :

aliakbar921853

Answer: 17.59 Hz and 4.87 m

Explanation:

The fundamental frequency of the sound from an open-open pipe is given as

f= [tex]\frac{v}{2L}[/tex]

where v= 343 m/s

L= 32 feet= [tex]\frac{32}{3.281}[/tex] = 9.75 m

So,

f= [tex]\frac{343}{2*9.75}[/tex] = 17.59 Hz

The length of open-closed tube is related to frequency by formula

f= [tex]\frac{v}{4L}[/tex]

or L=[tex]\frac{v}{4f}[/tex]

L= [tex]\frac{343}{4*17.59}[/tex]

L= 4.87 m

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