Answer :
Answer:
Mass of Sodium = 574.75 g
Mass of Chlorine = 886.25 g
Explanation:
The balance chemical equation for the synthesis of NaCl is,
2 Na + Cl₂ → 2 NaCl
Step 1: Find out moles of each reactant required,
According to balance chemical equation,
2 moles of NaCl is produced by = 2 moles of Na
So,
25 moles of NaCl will be produced by = X moles of Na
Solving for X,
X = 25 mol × 2 mol / 2 mol
X = 25 moles of Na
Similarly for Cl₂,
According to balance chemical equation,
2 moles of NaCl is produced by = 1 mole of Cl₂
So,
25 moles of NaCl will be produced by = X moles of Cl₂
Solving for X,
X = 25 mol × 1 mol / 2 mol
X = 12.5 moles of Cl₂
Step 2: Convert each moles to mass as;
Mass = Moles × Atomic Mass
For Na,
Mass = 25 mol × 22.99 g/mol
Mass = 574.75 g
For Cl₂,
Mass = 12.5 mol × 70.90 g/mol
Mass = 886.25 g
Mass of Sodium = 574.75 g and Mass of Chlorine = 886.25 g
The balanced chemical equation for the synthesis of NaCl:
The number of moles can be calculated by dividing given mass over molar mass.
2 Na + Cl₂ → 2 NaCl
Calculation for moles:
2 moles of NaCl is produced by = 2 moles of Na
So,
25 moles of NaCl will be produced by = x moles of Na
Solving for x,
x = 25 mol × 2 mol / 2 mol
x = 25 moles of Na
Similarly for Cl₂,
2 moles of NaCl is produced by = 1 mole of Cl₂
So,
25 moles of NaCl will be produced by = x moles of Cl₂
Solving for x,
x = 25 mol × 1 mol / 2 mol
x = 12.5 moles of Cl₂
Conversion of moles from mass:
Mass = Moles × Atomic Mass
For Na,
Mass = 25 mol × 22.99 g/mol
Mass = 574.75 g
For Cl₂,
Mass = 12.5 mol × 70.90 g/mol
Mass = 886.25 g
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