Answer:
Empirical Formula = NaClO₃
Explanation:
As the question is incomplete so we will assume that the question is asking for finding out the empirical formula of the compound made up of these elements,
Step 1: Calculate Moles of each element as:
Moles (Na) = 0.154 g / 22.99 g/mol = 0.006698
Moles (Cl) = 0.238 g / 35.45 g/mol = 0.006713
Moles (O) = 0.322 g / 16.00 g/mol = 0.02012
Step 2: Calculate mole ratio and simplify it,
Na Cl O
0.006698 0.006713 0.02012
0.006698/0.006698 0.006713/0.006698 0.02012/0.006698
1.00 1.00 3.00
Result:
Empirical Formula = NaClO₃
