Answer:
47.48 m
Explanation:
The horizontal range of an object can be estimated using the equation below:
[tex]S_{x} =[/tex][tex]\frac{v^{2}*sin (2\alpha)}{g}[/tex]
For the maximum horizontal range to occur, the angle [tex]\alpha[/tex] is 45°. Then, the horizontal range will be:
[tex]S_{x}[/tex] = [tex]\frac{v^{2}*sin 90}{g} = \frac{v^{2}}{g}[/tex]
In addition, the velocity (v) can be estimated using the equation below:
v = gt/2
Therefore, the maximum horizontal range is:
[tex]S_{x} = \frac{(gt/2)^{2}}{g}[/tex] = (9.81*4.4/2)^2 / 9.81 = 47.48 m
