The magnitude of the electric field is 1154 N/C
Explanation:
The magnitude of the electrostatic force experienced by a charged particle in an electric field is given by
[tex]F=qE[/tex]
where
F is the magnitude of the force
q is the magnitude of the charge
E is the magnitude of the electric field
In this problem, we have:
[tex]q=2.6\cdot 10^{-9} C[/tex] is the magnitude of the charge
[tex]F=3.0\cdot 10^{-6}N[/tex] is the magnitude of the force
Solving for E, we find the magnitude of the electric field:
[tex]E=\frac{F}{q}=\frac{3.0\cdot 10^{-6}}{2.6\cdot 10^{-9}}=1154 N/C[/tex]
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