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The monovalent salt concentration (the predominant solute in the blood cell) for a sample of red blood cells is 0.19 moles/liter. If one of these red blood cells were placed in pure water (at around room temperature, 300 K), and the cell comes to hydrostatic equilibrium with the water, what is the osmotic pressure of the cell (assuming it doesn't burst)? Provide your answer in kilopascals (1 kPa = 1x103 Pa). Again, be careful, salts dissociate when dissolved, and take care with the concentration (moles/liter vs moles/m3).

Answer :

Answer:

what is the osmotic pressure of the cell = 948.34KPa

Explanation:

The detailed and step by step calculation and appropriate formula is as shown in the attachment.

${teks-lihat-gambar} olumidechemeng

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