Ilakkya
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A factory produces some batteries daily. 7/8 of the batteries are packaged immediately. 2/3 of the
remaining batteries are sent to charity and the rest are faulty.
(a) Find the fraction of batteries that are faulty in the batch.​

Answer :

Answer:

[tex]\[\frac{1}{24}\][/tex]

Step-by-step explanation:

Let the total number of batteries produced daily be represented by x.

7/8 of the batteries are packaged immediately.

So the total number of packaged batteries = [tex]\[\frac{7x}{8}\][/tex]

Remaining batteries = [tex]\[x-\frac{7x}{8}\][/tex]

= [tex]\[\frac{x}{8}\][/tex]

Two third of the remaining batteries are sent to charity.

So the total number of batteries sent to charity= [tex]\[\frac{2}{3} * \frac{x}{8}\][/tex]

= [tex]\[\frac{x}{12}\][/tex]

Remaining batteries are faulty.

So the total number of faulty batteries = [tex]\[\frac{x}{8} - \frac{x}{12}\][/tex]

= [tex]\[\frac{3x - 2x}{24}\][/tex]

= [tex]\[\frac{x}{24}\][/tex]

So the faction of batteries which are faulty =

= [tex]\[\frac{x}{24} \div x\][/tex]

= [tex]\[\frac{1}{24}\][/tex]

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