I was wondering if someone could help me out, I’m not to sure how to answer this, I thought it was just adding the exponents since the bases are the same.

Answer:
Step-by-step explanation:
[tex]a^b*a^c=a^{b+c}\\(\frac{1}{2})^8 \times (\frac{1}{2} )^6=(\frac{1}{2})^{8+6} =(\frac{1}{2} )^{14}[/tex]