Answer :

Answer:

Amount invested at rate of 1% is $3000

And amount invested at rate of 7% is $4500

Explanation:

Let he invested $x at a rate of 1%

So amount invested at rate of 7% = x+1500 ( Given in question )\

Total interest for 1 year is given $345

Interest will be equal to [tex]SI=\frac{P\times r\times t}{100}[/tex], here P is amount to be invested r is rate of interest and n is time period

So total interest [tex]=\frac{x\times 1\times 1}{100}+\frac{(1500+x)\times 1\times 7}{100}=345[/tex]

[tex]x+7x+10500=34500[/tex]

8x = 24000

x = 3000

So amount invested at rate of 1% is $3000

And amount invested at rate of 7% = $3000+$1500 = $4500

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