Answer:
a. [tex]A=10u^{2}[/tex]
b. View graph
c. 6.40u
Step-by-step explanation:
knowing that the triangle area is equal to base by heigh between two, then:
[tex]A=\frac{bh}{2}=\frac{5*4}{2}=10u^{2}[/tex]
The length of the longest altitude of your triangle is:
[tex]c^{2}=a^{2}+b^{2}=5^{2}+4^{2}=25+16=41\\ c=\sqrt{41}=6.40u[/tex]
finally it can be seen that the position of the triangle does not matter, as long as the base and heigh are maintained, the area of the triangle will be the same
