Answer:
The answer to your question is FeSO₃
Explanation:
Data
Fe = 134 g
S = 76.9 g
O = 115 g
Process
1.- Convert the grams to moles for each element
For Fe
56 g of Fe ------------------- 1 mol
134 g of Fe ------------------- x
x = (134 x 1) / 56
x = 134/56
x = 2.39 moles
For S
32 g of S --------------------- 1 mol
76.9 g of S ------------------ x
x = (76.8 x 1) / 32
x = 2.4 moles
For O
16 g of O ---------------------- 1 mol
115 g of O ---------------------- x
x = (115 x 1)/ 16
x = 7.18 moles
2.- Divide by the lowest number of moles
Fe = 2.39/2.39 = 1
S = 2.4/2.39 = 1
O = 7.18/2.39 = 3
3.- Write the empirical formula
FeSO₃
