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A conducting spherical shell of inner radius r1 and outer radius r2 has a charge Q on it. An additional charge, also Q, is then added to the sphere. What is the resulting charge per unit area on the outer surface of the sphere?

Answer :

Answer:

Explanation:

Since the spherical shell is conducting , all the charge will lie on the outer surface .

Total charge

= Q +Q = 2Q

surface area = 4πr₂²

surface charge density = charge / surface area

= 2Q / 4πr₂²

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