Answer :
Answer:
Explanation:
Given
Temperature of gas [tex]T=25^{\circ}C\approx 298\ K[/tex]
Volume of gas [tex]V=31.5\ L\approx 31.5\times 10^{-3}\ m^3[/tex]
no of moles of gas [tex]n=3.81\ mol[/tex]
Using Ideal gas Equation to find the Pressure of gas
[tex]PV=nRT[/tex]
where P=Absolute Pressure
V=Volume
R=Universal gas constant
T=Temperature
[tex]P\times 31.5\times 10^{-3}=3.81\times 8.314\times 298[/tex]
[tex]P=\frac{3.81\times 8.314\times 298}{31.5\times 10^{-3}}[/tex]
[tex]P=299.66\ kPa[/tex]
And we know Atmospheric Pressure is [tex]101.325\ kPa[/tex]
Therefore Gauge pressure is given by
[tex]P_{gauge}=P-P_{atm}[/tex]
[tex]P_{gauge}=299.66-101.325[/tex]
[tex]P=198.34\ kPa[/tex]