Answer :
Answer:
Answer: Mole fraction of sucrose is 0.0369.
Explanation:
Mole fraction is the ratio of moles of a particular component to the total number of moles.
Given : 295 g of sucrose is dissolved in 405 g of water.
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
a) [tex]\text{Number of moles of sucrose}=\frac{295g}{342.3g/mol}=0.862moles[/tex]
b) [tex]\text{Number of moles of water}=\frac{405g}{18g/mol}=22.5moles[/tex][tex]\text {mole fraction of sucrose}=\frac{\text {moles of sucrose}}{\text {moles of water+moles of sucrose}}[/tex]
Putting in the values
[tex]\text {mole fraction of sucrose}=\frac{0.862}{22.5+0.862}=0.0369[/tex]
Thus mole fraction of sucrose is 0.0369.