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A tin can has a radius of 0.0410 m, and is 0.185 m high. if the air is removed from inside the can, how much force will the outside air(at 1 atm) exert on the bottle?(unit=N) PLEASE HELP ME I HAVE BEEN STUCK ON THIS QUESTION FOR A MONTH

Answer :

MathPhys

Answer:

0 N

Explanation:

The pressure inside the can is 0 atm, so the pressure difference between the inside and outside is 1 atm, or 101,325 Pa.  The pressure times the area equals the force.

However, force is a vector.  The force on one side of the can is countered by an equal and opposite force on the other side.  So the net force of the air on the can is 0 N.

${teks-lihat-gambar} MathPhys

Answer:

4825

Explanation:

Trust me

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