NCMIUM 1 Thlroduction lo Huncuons & Equalions FORME ZU19-ZUZU
TZU
Which ordered pair satisfies the inequality y < 2x + 6? Check all that apply.
A. (-1,8)
B. (-3, -12)
C. (0, 12)
D. (-2, 10)
E. (0,0)

Answer :

Option B: [tex](-3,-12)[/tex]

Option E: [tex](0,0)[/tex]

Explanation:

The inequality is [tex]y<2 x+6[/tex]

Now, we shall determine the ordered pairs which satisfy the inequality.

Option A: [tex](-1,8)[/tex]

Substituting, the coordinate [tex](-1,8)[/tex] in the inequality [tex]y<2 x+6[/tex], we get,

[tex]8<2(-1)+6\\8<-2+6\\8<4[/tex]

This is not possible.

Hence, the ordered pair [tex](-1,8)[/tex] does not satisfy the inequality.

Option A is not the correct answer.

Option B: [tex](-3,-12)[/tex]

Substituting, the coordinate [tex](-3,-12)[/tex] in the inequality [tex]y<2 x+6[/tex], we get,

[tex]-12<2(-3)+6\\-12<-6+6\\-12<0[/tex]

This is possible.

Hence, the ordered pair [tex](-1,8)[/tex]  satisfy the inequality.

Option B is the correct answer.

Option C: [tex](0,12)[/tex]

Substituting, the coordinate [tex](0,12)[/tex] in the inequality [tex]y<2 x+6[/tex], we get,

[tex]12<2(0)+6\\12<0+6\\12<6[/tex]

This is not possible.

Hence, the ordered pair [tex](0,12)[/tex] does not satisfy the inequality.

Option C is not the correct answer.

Option D: [tex](-2,10)[/tex]

Substituting, the coordinate [tex](-2,10)[/tex] in the inequality [tex]y<2 x+6[/tex], we get,

[tex]10<2(-2)+6\\10<-4+6\\10<2[/tex]

This is not possible.

Hence, the ordered pair [tex](-2,10)[/tex] does not satisfy the inequality.

Option D is not the correct answer.

Option E: [tex](0,0)[/tex]

Substituting, the coordinate [tex](0,0)[/tex] in the inequality [tex]y<2 x+6[/tex], we get,

[tex]0<2(0)+6\\0<0+6\\0<6[/tex]

This is possible.

Hence, the ordered pair [tex](0,0)[/tex]  satisfy the inequality.

Option E is the correct answer.

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