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A boat is traveling east across a river that is 112 meters wide at 8 meters per second. If the river has a northward current of a 5 meters per second, what is the resultant speed of the motorboat rounded to the nearest tenth?
A)8.6 m/s
B)3.0 m/s
C)13.0 m/s
D)9.4m/s

Answer :

MathPhys

Answer:

D) 9.4 m/s

Step-by-step explanation:

The boat has an eastward speed of 8 m/s and a northward speed of 5 m/s.  The resultant speed can be found with Pythagorean theorem:

v² = (8 m/s)² + (5 m/s)²

v = 9.4 m/s

Answer:

This is the concept of application of the Pythagorean theorem. The resultant speed of the motorboat which is crossing the river that has a northward current of 5 m/s at a speed of 8 m/s will be given by:

c^2=a^2+b^2

c^2=8^2+5^2

c^2=64+25

c^2=89

c=sqrt89

c=9.4 m/s

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