Answer :

musiclover10045

2x-3y <= 12

Subtract 2x from both sides:

-3y <= 12 - 2x

Divide all terms by -3 ( when you divide an inequality by a negative value you must also reverse the inequality sign)

y >= -4 +2/3x or can be written as y >=2/3x -4

meredith48034

Answer:

[tex]2x - y \leqslant 12 \\ -3 y \leqslant - 2x + 12 \\ 3y \geqslant 2x - 12 \\ y \geqslant \frac{2}{3} x - 4[/tex]

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