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A cart of mass m moving right at speed v with respect to the track collides with a cart of mass 0.7m moving left.
What is the initial speed of the second cart if after the collision the carts stick together and stop?
Express your answer in terms of some or all of the variables m and v.

Answer :

Answer:

10v / 7

Explanation:

Using the conservation law of momentum

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

m v - 0.7 m v₁ =  ( 0.7 m + m) 0 m/s since the cart stuck together after collision. taken right to be positive and left to be negative

m v - 0.7 m v₁ = 0

- 0.7 m v₁ = -m v

v₁ = -m v / - 0.7 m = 10v / 7

Answer:

10/7 * V.

Explanation:

Momentum = mass * velocity

Given:

Mass of cart 1 = M1

Mass of cart 2 = M2

= 0.7M1

Initial velocity of cart 1 = Vi1

= V

Initial velocity of cart 2 = Vi2

Final velocity = V

= 0

Initial momentum of cart 1 + initial momentum of cart 2 = total mass of both cart * velocity

M1 * Vi1 + M2 * Vi2 = (M1 + M2) * V

= M * V - (0.7M * Vi2) = (M + 0.7M) * 0

= MV - 0.7M * Vi2 = 0

Vi2 = 10/7 * V.

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