Answer :
Answer:
(a) [tex]T_{1}=490N[/tex]
(b) [tex]T_{2}=240N[/tex]
Explanation:
For Part (a)
Given data
The box moves up at steady 5.0 m/s
The mas of box is 50 kg
As ∑Fy=T₁ - mg=0
[tex]T_{1}=mg\\T_{1}=(50kg)(9.8m/s^{2} ) \\T_{1}=490N[/tex]
For Part(b)
Given data
[tex]v_{iy}=5m/s\\ a_{y}=-5.0m/s^{2}[/tex]
As ∑Fy=T₂ - mg=ma
[tex]T_{2}=mg+ma_{y}\\T_{2}=m(g+ a_{y})\\T_{2}=50kg(9.8-5.0) \\T_{2}=240N[/tex]