A ship is sailing on the sea. It travels 50 miles at 60° to the horizontal. Then the ship travels 90 miles at 30° to the horizontal
before coming to a stop. How many miles North has the ship travel?
A)
25+ 4573
B)
25V3+45
D)
70
E)
140

Answer :

calculista

Answer:

[tex](25\sqrt{3}+45)\ miles[/tex]

Step-by-step explanation:

we know that

The total vertical distance (total miles North) traveled is equal to

[tex]d=50sin(60^o)+90sin(30^o)[/tex]

Remember that

[tex]sin(60^o)=\frac{\sqrt{3}}{2}[/tex]

[tex]sin(30^o)=\frac{1}{2}[/tex]

substitute

[tex]d=50(\frac{\sqrt{3}}{2})+90(\frac{1}{2})[/tex]

[tex]d=(25\sqrt{3}+45)\ miles[/tex]

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