Answer :
Answer:
[tex]x=\frac{1}{26}[/tex]
Step-by-step explanation:
Given Equation:
[tex]\frac{2}{3}(\frac{1}{2x}+12 ) =\frac{1}{2}(\frac{1}{3x} +14)-3[/tex]
Solving L.H.S and R.H.S and taking the terms of x' to one side and the constants to the other side.
[tex](\frac{2}{3}) \frac{1}{2x} +\frac{2}{3}(12) = (\frac{1}{2}) (\frac{1}{3x})+\frac{1}{2}(14)-3\\ \\ \frac{2}{6x}+(2*4)=\frac{1}{6x}+7-3 \\\\ \frac{1}{3x} +8=\frac{1}{6x} +4\\\\\frac{1}{6x}- \frac{1}{3x} =8-4\\\\\frac{1(1)-1(2x)}{6x}=4\\\\\frac{1-2x}{6x}=4\\ 1-2x=24x\\24x+2x=1\\26x=1[/tex]
[tex]x=\frac{1}{26}[/tex]
So, the value of 'x' is
[tex]x=\frac{1}{26}[/tex]