Answer :
Answer:
The magnitude of the maximum radial acceleration of the stone is 122.034 m/s^2
Explanation:
Maximum radial acceleration (a) = w^2r
w = v/r
w^2 = (v/r)^2 = v^2/r^2
a = v^2/r^2 × r = v^2/r
v is the maximum speed the stone attains = 12 m/s
r is the radius of the circular path = 1.18 m
a = 12^2/1.18 = 144/1.18 = 122.034 m/s^2
The magnitude of the maximum radial acceleration of the stone is 122.03 m/s².
Given Data:
The mass of granite is, m = 2.30 kg.
The radius of circular path is, r = 1.18 m.
The maximum speed attained by a stone is, v = 12.0 m/s.
In the given problem, the magnitude of the maximum of radial acceleration is nothing but the centripetal acceleration itself. And the expression for the centripetal acceleration is given as,
[tex]a = \dfrac{v^{2}}{r}[/tex]
Solving as,
[tex]a = \dfrac{12.0^{2}}{1.18}\\\\a = 122.03 \;\rm m/s^{2}[/tex]
Thus, we can conclude that the magnitude of the maximum radial acceleration of the stone is 122.03 m/s².
Learn more about the centripetal acceleration here:
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