Answer :
Answer:
Explanation:
Screen distance D = 1.5 m
slit separation d = .15 x 10⁻³ m
distance of 5 th maxima = 2.8 x 10⁻² m
distance of n th maxima = n x λ D/d
2.8 x 10⁻² = 5 x ( λ 1.5 / .15 x 10⁻³ )
λ = (2.8 x 10⁻² x .15 x 10⁻³ ) / (5 x 1.5 )
= .42 x 10⁻⁵ / 7.5
.056 x 10⁻⁵
= 56 x 10⁻⁸ m
= 5600 A
Answer:
The wavelength of the light is 560 nm.
Explanation:
Given that,
Distance from the central maximum y= 2.8 cm
Distance D=1.5 m
Distance between the slit = 0.15 m
We need to calculate the wavelength of the light
Using formula of constructive interference
[tex]m\lambda=\dfrac{yd}{D}[/tex]
[tex]\lambda=\dfrac{yd}{mD}[/tex]
Put the value into the formula
[tex]\lambda=\dfrac{2.8\times\times10^{-2}\times0.15\times10^{-3}}{5\times1.5}[/tex]
[tex]\lambda=5.6\times10^{-7}[/tex]
[tex]\lambda=560\ nm[/tex]
Hence, The wavelength of the light is 560 nm.