Answer :

Hrishii

Step-by-step explanation:

[tex]In\: \triangle ABC \:\&\: \triangle ADC\\\\

\angle BAC\cong \angle DAC... (given) \\\\

AC \cong AC....(common) \\\\

\angle ACB\cong \angle ACD... (each\: 90°)\\\\

\therefore \triangle ABC \cong \triangle ADC.. (By\:ASA) [/tex]

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