Answer :
Answer:
a) 4u + 2v = (8, 12, 14)
b) 2u - v = (0, 6, 1)
c) |u + 4v| = 16.9
Step-by-step explanation:
When we add/subtract vectors, we add/subtract their components. For example
a = (a1,a2,a3)
b = (b1,b2,b3)
a+b = (a1 + b1, a2 + b2, a3 + b3)
|a| is the modulus of vector a, given by
[tex]|a| = \sqrt{a1^{2} + a2^{2} + a3^{3}}[/tex]
In this problem, we have that:
u = (1,3,2)
v = (2,0,3)
(a) 4u+2v
4u = 4(1,3,2) = (4,12,8)
2v = 2(2,0,3) = (4,0,6)
4u + 2v = (8, 12, 14)
(b) 2u-v
2u = 2(1,3,2) = (2,6,4)
v = (2,0,3)
2u - v = (0, 6, 1)
(c) |u + 4v|
u = (1,3,2)
4v = 4(2,0,3) = (8,0,12)
u + 4v = (9,3,14)
[tex]|u + 4v| = \sqrt{9^{2} + 3^{2} + 14^{2}} = 16.9[/tex]