Answer:
( x + 4 ) ( x + 2 )
Step-by-step explanation:
There are two ways two approach it.
The first one is:
[tex] {x}^{2} + 6x + 8 \\ {x}^{2} + 2x + 4x + 8 \\ x(x + 2) + 4(x + 2) \\ (x + 4)(x + 2)[/tex]
The other way is by finding the roots through the quadratic formula, and then factoring out. In other words:
x^2 + 6x + 8 = 0
a = 1
b = 6
c = 8
∆ = b^2 - 4ac = 4
x = ( -b +- √∆ ) / 2a
x = - 4. or x = -2
then, when p,q are the two roots of
ax^2 + bx +c =0, it can be factored out like this:
a ( x - p ) ( x - q )
1 ( x - ( -4 ) ) ( x - ( -2 ) ) = ( x + 4 ) ( x + 2 )
