Answer:
[tex]38x^2+14x-6[/tex]
Step-by-step explanation:
In the Cuboid in the figure, the length, width and height are given i.e
[tex]Length(l)= 4x+3\\Width(w)=x\\Height(h)=3x-1[/tex]
Finding the Total surface area of the cuboid :
T.S.A of a cuboid=
[tex]2[l*w+w*h+h*l]\\=2[(4x+3)*x+x*(3x-1)+(3x-1)*(4x+3)][/tex]
Expanding the equation:
[tex]2[(4x^2+3x)+(3x^2-x)+(12x^2+9x-4x-3)]\\2[4x^2+3x+3x^2-x+12x^2+5x-3)]\\2[19x^2+7x-3]\\38x^2+14x-6[/tex]
So, the expanded form of the area of the given cuboid is:
[tex]38x^2+14x-6[/tex]