Answer :
[tex]\text{Hey there!}[/tex]
[tex]\text{Use the quadratic formula to solve this!}[/tex]
[tex]\mathsf{Formula: ax^2+bx+c=0}[/tex]
[tex]\mathsf{ax^2=x^2}\\\mathsf{bx=4x}\\\mathsf{c=6}\\\mathsf{0=0}[/tex]
[tex]\rightarrow\ =\mathsf{-1x^2+4x+6=0}[/tex]
[tex]\bf{x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\leftarrow \ \mathsf{The\ other\ formula}[/tex]
[tex]\bf{x= \dfrac{(-4)\pm\sqrt{(4)^2-4(-1)(6)}}{2(-1)}}[/tex]
[tex]\mathsf{(4)^2-4(-1)(6)}\\\mathsf{4^2=16}\\\mathsf{16-4(-1)(6)}\\\mathsf{4(-1)=-4}\\\mathsf{16-(-4)(6)}\\\mathsf{-4(6)=-24}\\\mathsf{16-(-24)=16+24}\\\mathsf{=40}[/tex]
[tex]\mathsf{2(-1)=-2}[/tex]
[tex]\mathsf{x=\dfrac{-4\pm\sqrt{40}}{-2}}[/tex]
[tex]\mathsf{\sqrt{40}\ =\ 2\sqrt{10}}}[/tex]
[tex]\huge\text{\bf{SOLVE that above and you have your}}}\\\huge\text{\bf{ANSWER}}[/tex]
[tex]\boxed{\boxed{\bf{Answer: x=2-\sqrt{10}\ or\ x=2+2\sqrt{10}}}}\checkmark[/tex]
[tex]\text{Good luck on your assignment and enjoy your day!}[/tex]
~[tex]\dfrac{\frak{LoveYourselfFirst}}{:)}[/tex]