Answer :

MathPhys

Answer:

f'(x) = 3(x−1)²

Step-by-step explanation:

Definition of derivative is:

f'(x) = lim(h→0) [f(x + h) − f(x)] / h

f(x) = (x−1)³, so the derivative is:

f'(x) = lim(h→0) [(x−1+h)³ − (x−1)³] / h

f'(x) = lim(h→0) [(x−1)³ + 3(x−1)²h + 3(x−1)h² + h³ − (x−1)³] / h

f'(x) = lim(h→0) [3(x−1)²h + 3(x−1)h² + h³] / h

f'(x) = lim(h→0) [3(x−1)² + 3(x−1)h + h²]

f'(x) = 3(x−1)²

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