Step-by-step explanation:
[tex]g(x) = 2x + \frac{2}{x} - A \\ \\ \therefore \: g(1) = 2 \times 1 + \frac{2}{1} - A \\ \\ \therefore \: g(1) = 2 + 2 - A \\\therefore \: g(1) = 4 - A ...(1) \\ \because \: g(1) = - 2...(2)(given) \\ from \: equations \: (1) \: and \: (2) \\ - 2 = 4 - A \\ \\ \therefore \: - 2 - 4 = - A \\ \\ \therefore \: -6= - A \\ \\ \huge \red{ \boxed{\therefore \: A = 6}}[/tex]
