A gas has a volume of 490. mL at a temperature of -35.0 degrees C. What volume would the gas occupy at 42.0 degrees Celsius? Please show work.

Answer :

skyluke89

Answer:

648.5 mL

Explanation:

Here we will assume that the pressure of the gas is constant, since it is not given or specified.

Therefore, we can use Charle's law, which states that:

"For an ideal gas kept at constant pressure, the volume of the gas is proportional to its absolute temperature"

Mathematically:

[tex]\frac{V}{T}=const.[/tex]

where

V is the volume of the gas

T is its absolute temperature

The equation can be rewritten as

[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]

where in this problem we have:

[tex]V_1=490 mL[/tex] is the initial volume of the gas

[tex]T_1=-35.0^{\circ} + 273 = 238 K[/tex] is the initial temperature

[tex]T_2=42.0^{\circ}+273=315 K[/tex] is the final temperature

Solving for V2, we find the final volume of the gas:

[tex]V_2=\frac{V_1 T_2}{T_1}=\frac{(490)(315)}{238}=648.5 mL[/tex]

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