Answer :
Answer:
3.37 x 10^7 Kg
Step-by-step explanation:
Starting with the general solution equation for differential equation involving exponential population growth
[tex]y =\frac{c}{1 + Ae^{-kt} }[/tex]
c = 9 x 10^7Kg
k = 0.74 per year
[tex]y =\frac{9 * 10^{7} }{1 + Ae^{-0.74t} }[/tex]
[tex]A=\frac{c- y(0) }{y(0) } = \frac{9*10^{7} - 2*10^{7} }{2*10^{7}} \\\\A=3.5[/tex]
[tex]y =\frac{9 * 10^{7} }{1 + Ae^{-0.74t} } \\\\y =\frac{9 * 10^{7} }{1 + 3.5e^{-0.74t} } \\\\A year later , t= 1\\y =\frac{9 * 10^{7} }{1 + 3.5e^{-0.74*1} } = 33709144.04[/tex]
3.37 x 10^7 Kg