Answer :
Answer : The temperature of liquid is, 369.9 K
Explanation :
The Clausius- Clapeyron equation is :
[tex]\ln (\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}\times (\frac{1}{T_1}-\frac{1}{T_2})[/tex]
where,
[tex]P_1[/tex] = vapor pressure of liquid at 373 K = 681 torr
[tex]P_2[/tex] = vapor pressure of liquid at normal boiling point = 760 torr
[tex]T_1[/tex] = temperature of liquid = ?
[tex]T_2[/tex] = normal boiling point of liquid = 373 K
[tex]\Delta H_{vap}[/tex] = heat of vaporization = 40.7 kJ/mole = 40700 J/mole
R = universal constant = 8.314 J/K.mole
Now put all the given values in the above formula, we get:
[tex]\ln (\frac{760torr}{681torr})=\frac{40700J/mole}{8.314J/K.mole}\times (\frac{1}{T_1}-\frac{1}{373K})[/tex]
[tex]T_1=369.907K\approx 369.9K[/tex]
Hence, the temperature of liquid is, 369.9 K