Answer :
Answer:
[tex]q=-2.22*10^{-11}C[/tex]
Explanation:
The potential produces by a point charge is given by:
[tex]V=\frac{kq}{r}[/tex]
Here, k is the Coulomb constant, q is the signed magnitude of the point charge and r is the distance between the charge and the point at which the electric potential is measured. Solving for q:
[tex]q=\frac{rV}{k}\\q=\frac{1*10^{-3}m(-200V)}{8.99*10^9\frac{V\cdot m}{C}}\\q=-2.22*10^{-11}C[/tex]
The magnitude of the point charge is =2.22×10^-11C.
The formula for charge is q=rv÷k
Where;
k is the Coulomb constant
q is the signed magnitude of the point charge r is the distance between the charge and the point at where electric potential is measured.
q=?
r=1 ×10^-3
v= -200v
k= 8.99 ×10^9
q= 11 ×10^-3 ×200v/8.99×0^9
q =2.22×10^-11C.
What is Magnitude of magnetic field?
Magnitude of a magnetic field is the force that act on a charge or test charge.
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