Answer :
Explanation:
It is known that the relation between force and acceleration is as follows.
F = -ma ............ (1)
Also, acceleration (a) = [tex]\frac{v^{2} - u^{2}}{2s}[/tex] ......... (2)
The given data is as follows.
v = 0, u = 14 m/s, s = 1
Therefore, putting the values of expression (2) into expression (1) as follows.
F = [tex]-m \times \frac{v^{2} - u^{2}}{2s}[/tex]
= [tex]-61 kg \times \frac{(0)^{2} - (14)^{2}}{2 \times 1}[/tex]
= 5978 N
thus, we can conclude that net force on the person if he or she is wearing a seat belt and if the air bag deploys is 5978 N.