Answer :
Answer:
Vapors
Explanation:
We take into account that all the energy from the lightning has been transformed into steam.
[tex]\Delta U = Q - W\\Q = mC \Delta T\\Q = mL[/tex]
We calculate the amount of energy required by water to convert into steam.
[tex]Q_{water} = 50 \times \times 4180 \times (100-37)\\= 1.132 \times 10^7 \ J[/tex]
[tex]Q_{change\ to\ steam} = 50 \times 2.256 \times 106 \\= 1.128 \times 10^8 \ J[/tex]
[tex]Q_{total} = 1.132 \times 10^7 + 1.128 \times 10^8\\= 1.126 \times 10^8 \ J[/tex]
From the lightning we received [tex]10^{10} \ J[/tex] of energy, out of which [tex]1.126 \times 10^8[/tex] has been used to convert the water into steam.
Energy left = [tex]10^{10} - 1.126 \times 10^8 = 9.88 \times 10^9 \ J[/tex]
We use this energy to convert steam into vapors.
[tex]Q = \Delta E[/tex]
[tex]Q = \Delta E = mc (T_{f} - T{i})\\T_{f} = \frac {\Delta E}{mc} + T_{i}\\ \\T_{f} = 100 + \frac{9.88 \times 10^{10}}{50 \times 1970}\\T_{f} = 100 + 10^8\\T_{f} = 10 ^{ \ 8} \ {^ \circ } C[/tex]
With this temperature, we can easily interpret that the vapors will be dissociated in hydrogen and oxygen particles.