Answer :
Answer:
a.) [tex]V_{RMS}[/tex] = 141 volts
b.) The amplitude A= 1.414 × 220 = 311 volts.
Step-by-step explanation:
The equation of the voltage for the given supply is mentioned as
E(t) = 200 sin(200πt). The equation for a voltage is given by
E(t) = [tex]V_{maximum} \times sin(2 \times \pi \times f \times t)[/tex]
where f is the frequency of the supply.
Therefore [tex]V_{peak}[/tex] (or maximum voltage)= 200 volts.
a.) The RMS voltage can be found from the equation
[tex]V_{RMS} = \frac{V_{peak}}{\sqrt{2} } = \frac{200}{\sqrt{2} }= 141.42 volts[/tex]
The answer is 141 volts
b. ) It is also mentioned that the requirement for many is an RMS voltage of 220 V.
The corresponding amplitude of the voltage A that is needed will be
E(t) = Asin(200πt).
We can find A from the expression used in a.) .
Therefore
A = = 1.414 × 220 = 311 volts.