Answer:
The calculation in step 3 is wrong
Step-by-step explanation:
1) The mean of a dataset is given by the sum of the values of the dataset divided by the number of values.
In this problem, the dataset is
35, 16, 23, 42, 19
And the number of data is
N = 5
So the mean is
[tex]\bar x=\frac{35+16+23+42+19}{5}=27[/tex]
So, step 1 is correct.
2)
The absolute deviation of a value in the dataset is the absolute value of its difference from the mean value:
[tex]\sigma_i = |x_i-\bar x|[/tex]
Since here the mean value is
[tex]\bar x=27[/tex]
Then for each of the values in this dataset, we have:
[tex]\sigma_{1}=|35-27|=8\\\sigma_{2}=|16-27|=11\\\sigma_{3}=|23-27|=4\\\sigma_{4}=|42-27|=15\\\sigma_{5}=|19-27|=8[/tex]
So calculations in step 2 are also correct.
3)
The mean absolute deviation is given by the sum of the absolute deviations for each data divided by the number of values in the dataset.
Therefore in this problem, it is:
[tex]\bar \sigma = \frac{\sum \sigma_i}{N}=\frac{8+11+4+15+8}{5}=9.2[/tex]
While the result reported by Dora is 9.5: therefore, this step is not correct.
