Answer :
Answer:
Explanation:
mass of first puck, m1 = 0.450 kg
initial velocity of first puck, u1 = 5.80 m/s east
mass of second puck, m2 = 0.9 kg
initial velocity of second puck, u2 = 0
Let v1 and v2 are the final velocities of the pucks after collision.
Use conservation of momentum
m1 x u1 + m2 x u2 = m1 x v1 + m2 x v2
0.45 x 5.8 + 0.9 x 0 = 0.45 x v1 + 0.9 x v2
5.8 = v1 + 2 v2 ..... (1)
As the collision is perfectly elastic, the coefficient of restitution, e = 1
Use the formula for the coefficient of restitution
[tex]e=\frac{v_{1}-v_{2}}{u_{2}-u_{1}}[/tex]
0 - 5.8 = v1 - v2
v2 - v1 = 5.8 .... (2)
Adding equation (1) and equation (2), we get
v2 = 1.93 m/s and then v1 = - 3.87 m/s