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The earth has a vertical electric field at the surface, pointing down, that averages 119 N/C . This field is maintained by various atmospheric processes, including lightning. What is the excess charge on the surface of the earth

Answer :

sebasacevedop

Answer:

[tex]q=5.37*10^{5}C[/tex]

Explanation:

If we assume that the Earth is a spherical conductor, according to  Gauss's Law, the electric field is given by:

[tex]E=\frac{kq}{r^2}[/tex]

Here k is the Coulomb constant, the excess charge on the Earth's surface and r its radius. Solving for q:

[tex]q=\frac{Er^2}{k}\\q=\frac{119\frac{N}{C}(6.371*10^6m)^2}{8.99\frac{N\cdot m^2}{C^2}}\\q=5.37*10^{5}C[/tex]

okpalawalter8

We have that the excess charge on the surface of the earth  is mathematically given as

  • Q=4.92*19^{5}C

From the question we are told

  • The earth has a vertical electric field at the surface, pointing down, that averages 119 N/C .
  • This field is maintained by various atmospheric processes, including lightning.
  • What is the excess charge on the surface of the earth

Charge

Generally the equation for the Charge   is mathematically given as

[tex]Q=E*4\pir^2e_0\\\\Therefore\\\\Q=108*4+\pi(6.4*10^6)^2*8.85*10^12\\\\[/tex]

Q=4.92*19^{5}C

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