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A 9.0 Ω resistor and a 5.0 Ω resistor are connected in parallel across a 9.0 V battery. Find the following.

(a) the current through each resistor i9.0 = 1 A i5.0 = 1.8 A

(b) the voltage drop across each resistor V9.0 = V V5.0 = V

Answer :

JhoanEusse

Answer:

a) [tex]i_9=1.0A [/tex] and [tex]i_5=1.8A [/tex]

b) [tex]V_9=9.0V [/tex] and [tex]V_5=9.0V [/tex]

Explanation:

b) For a circuit with resistance on series the voltage drop in each resistor of the circuit is the same because resistances share nodes, and it's equal the voltage provided by the battery so:

[tex]V_9=9.0V [/tex]

[tex]V_5=9.0V [/tex]

b) Now, knowing the voltage drop on each resistor we can calculate the current across each of them using Ohm's law:

[tex]i=\frac{V}{R} [/tex]

with i the current, V the voltage and R the resistance, so:

[tex]i_9=\frac{9.0}{9.0}=1.0A [/tex]

and

[tex]i_5=\frac{9.0}{5.0}=1.8A [/tex]

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