Answered

Jake is solving x^2-6x+5=0 by completing the square his steps are shown below step 1. x^2-6x=-5 step 2. x^-6x+9=-5+9 step 3. (x-6)^2=4 Step 4. sq root (x-6)^2=sq root 4 step 5. x-6=+- 2 step 6. x=6+-2 step 7. x=8 and x =4. which step is Jakes error in.

Answer :

calculista

Answer:

Jake's error in step 3

Step-by-step explanation:

we have

[tex]x^{2} -6x+5=0[/tex]

Complete the square

step 1

Group terms that contain the same variable, and move the constant to the opposite side of the equation

[tex]x^{2} -6x=-5[/tex]

step 2

Complete the square. Remember to balance the equation by adding the same constants to each side

[tex]x^{2} -6x+9=-5+9[/tex]

[tex]x^{2} -6x+9=4[/tex]

step 3

Rewrite as perfect squares

[tex](x-3)^{2}=4[/tex]

Jake's error in step 3

He placed 6 instead of 3 in the left side

step 4

take square root both sides

[tex]\sqrt{(x-3)^2} =\sqrt{4}[/tex]

step 5

[tex](x-3)=\pm2[/tex]

step 6

[tex]x=3\pm2[/tex]

step 7

x=5 and x=1

Other Questions