Answer :
[tex]\sqrt{x^{2} + y^{2}-8x +16}[/tex] and mod(y-3)
Step-by-step explanation:
Step 1 :
Given the focus is at (4,0) and the directrix is y = 3. We have to find the 2 equations which relate the distance of the given focus and the given directrix to any point (x, y) on the parabola
Step 2 :
The distance between a point P(x,y) given on the parabola and the focus (4,0)
is
[tex]\sqrt{(x-4)^{2} + (y-0)^{2} } = \sqrt{x^{2}+16-8x + y^{2} } = \sqrt{x^{2} + y^{2}-8x +16}[/tex]
Step 3 :
The distance between the point P of (x,y) and the directrix line y = 3 is
mod (y-3)
So the 2 required equations are
[tex]\sqrt{x^{2} + y^{2}-8x +16}[/tex] and mod(y-3)
Answer:
View attached image
Step-by-step explanation:
First formula is directrix-y
Second formula is the distance formula. Just plug in the (x,y) into it.
