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Consider the parabola with a focus at the point (4,0) and directrix y = 3.
Which two equations can be used to correctly relate the distances from the
focus and the directrix to any point (x, y) on the parabola?

Answer :

[tex]\sqrt{x^{2} + y^{2}-8x +16}[/tex] and mod(y-3)

Step-by-step explanation:

Step 1 :

Given the focus is at (4,0) and the directrix is y = 3. We have to find the 2 equations which relate the distance of the  given focus and the given directrix to any point (x, y) on the parabola

Step 2 :

The distance between a point P(x,y) given on the parabola and the focus (4,0)

is

[tex]\sqrt{(x-4)^{2} + (y-0)^{2} } = \sqrt{x^{2}+16-8x + y^{2} } = \sqrt{x^{2} + y^{2}-8x +16}[/tex]

Step 3 :

The distance between the point P of (x,y) and the directrix line y = 3 is

mod (y-3)

So the 2 required equations are

[tex]\sqrt{x^{2} + y^{2}-8x +16}[/tex] and mod(y-3)

Answer:

View attached image

Step-by-step explanation:

First formula is directrix-y

Second formula is the distance formula. Just plug in the (x,y) into it.

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